Help with Beastmode on Count with Condition

user077529

Hello, I feel like this should be a simple thing to do, but am stumped.

I am trying to do a count of order numbers where there is a condition to be met. Is there a if function that I can follow to do this?

For example, there is a list of vendors, some of which have registered and some have not. I want to count the # of orders the vendor has for 1) if they are registered and 2) if they are not registered in two separate columns.

I tried a few things, but can't seem to get it..

1) if 'isRegistered' = 'True' then count(OrderNo)

2) case when 'isRegistered' = 'True' then count(OrderNo) else 0 end. This step kind of works but whenever 'isRegistered' = 'False', it will just display as 0.

Thank you!

GrantSmith

Hi @user077529

You can use a CASE statement to conditionally count values in a beast mode. You're close but yours is only counting everything if isRegistered is true. You want something like this:

Registered count

COUNT(CASE WHEN `isRegistered` = 'True' THEN `OrderNo` END)

Non-Registered.

COUNT(CASE WHEN `isRegistered` = 'False' THEN `OrderNo` END)

user077529

Hey Grant,

That's really helpful, thank you! Is there a way to do this if the value is null? For example...

count(case when 'isRegistered' = NULL then 'OrderNo' END)

And vice versa is there a way to count OrderNo if 'isRegistered' has ANY populated value, for example:

count(case when 'isRegistered' not NULL then "OrderNo' END)

MarkSnodgrass

@user077529

you would do isRegistered IS NULL and isregistered IS NOT NULL when evaluating nulls.