3+ Consecutive days
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You are going to need to utilize some rank and window functions to determine if you have 3 or more consecutive dates. I would recommend using Magic ETL and the Rank & Window tile. You would use the Lag function to check for consecutive days for starters.
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Hi @Hiraayub
You can utilize a beast mode LAG and LEAD functions to determine if it's in a 3+ day run.
LAG 1 and LEAD 1 = Day with one before and after
LAG 2 = Day with two before
LEAD2 = Day with two after
CASE WHEN (LAG(MAX(`Date`)) OVER (ORDER BY `Date`) = `Date` - INTERVAL '1' DAY AND LEAD(MAX(`Date`)) OVER (ORDER BY `Date`) = `Date` + INTERVAL '1' DAY) THEN 'INCLUDE' WHEN LAG(MAX(`Date`)) OVER (ORDER BY `Date`) = `Date` - INTERVAL '2' DAY THEN 'INCLUDE' WHEN LEAD(MAX(`Date`)) OVER (ORDER BY `Date`) = `Date` + INTERVAL '2' DAY THEN 'INCLUDE' END
Then just filter on this for any record with INCLUDE
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the problem with window functions in analyzer in this context is that you MUST show date on the axis in order for the lag function to work.
I assume you'd only want to show rows if there were 3 consecutive days of xyz status.
if my assumption is correct, you'd want to implement your lag calc in ETL so that you have a column to work with as @MarkSnodgrass suggests.
you may want to implement lag(date, 1) , lag(date, 2), lag(date, 3) and add them as columns. From there you could use datediff functions in beast mode to decide whether to display the columns or not.
Jae Wilson
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I'm so new to this and having a hard time with lag() & lead().
Yes you have assumed it right "I assume you'd only want to show rows if there were 3 consecutive days of xyz status."
This is really helpful and helps me understand what exactly needs to be done, I will play around with this.
Thank you!
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@jaeW_at_Onyx I'm not sure if I'm doing this right.
If you look at the picture on Oct 5th where it says 'Y' it shows the next 2 dates Sept 29th & Sept 28th but both of those have 'N'.
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