Day of Year in Redshift

Does Domo's Redshift support day of year?


I'm trying to parse my date column using the formulas and none work:


date_part(doy, "date") as "day of year"

date_part(dy, "date") as "day of year"

date_part(yearday, "date") as "day of year"

date_part(dayofyear, "date") as "day of year"


In the Redshift documentation this should work:

Best Answer

  • MarkSnodgrass
    MarkSnodgrass Portland, Oregon 🥷
    Answer ✓

    Another date function you can use in Redshift is Extract. I use it and it looks like this:

    extract(year from "dateofevent")  DateofEventYear,

    extract(day from "dateofevent") DayofEvent,

    I am able to use the date_part function as @jaeW_at_Onyx suggests, so I'm not sure what might be going on with that function in your instance, but maybe you will have better luck with the Extract function.

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  • jaeW_at_Onyx
    jaeW_at_Onyx Budapest / Portland, OR 🔴

    What error message did you get?  This works fine.


    select date_part(dayofyear, cast('2020-02-14' as date))



    Is your Date column a date or text?


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  • D-Rab
    D-Rab ⚪️

    select *,
    date_part(y,"date") as "year",
    (case when date_part(q,"date") <= 2 then 1 else 2 end) as "half year",
    date_part(q,"date") as "quarter",
    date_part(m,"date") as "month",
    date_part(dayofyear, "date") as "day of year"
    from "group_by"


    Date is a date field, not text. It wasn't throwing an error for any of the other date_part functions in this query.

  • D-Rab
    D-Rab ⚪️

    The database reported a syntax error: [Amazon](500310) Invalid operation: Invalid datetime part in DATE_PART(). Details: ----------------------------------------------- error: Invalid datetime part in DATE_PART(). code: 8001 context: query: 8206522 location: datetime


    That's the error I'm getting. it's from the dayofyear line of the query.